How do you find all six trigonometric function of #theta# if the point #(sqrt2,sqrt2)# is on the terminal side of #theta#?

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Answer 1 · 2018-06-20T14:18:34

As below.

#(x,y) = (sqrt2, sqrt2)#

#tan theta = y/x = sqrt 2 / sqrt2 = 1, theta = pi/4#

#cot theta = cot (pi/4) = 1 / tan (pi/4) = 1#

#sin theta = sin (pi/4)= 1 / sqrt2#

#cos theta = cos (pi/4) = 1/sqrt2#

#csc (theta) = 1 / sin theta = 1/ sin(pi/4) = sqrt2 #

#sec (theta) = 1/cos theta = 1 / cos (pi/4) = sqrt2 #