Theoretical Yield?

K 2 CO 3 (s) + 2HCl (aq) --->2KCl (aq) + H 2 O (l) + CO 2 (g)
What would be the theoretical yield of Potassium Chloride when 41.46 g of potassium carbonate reacts with excess
hydrochloric acid?

1 Answer
Ernest Z.
Jun 18, 2018

The theoretical yield of #"KCl"# is 44.73 g.

Explanation:

You know that you will need a balanced chemical equation with masses, moles, and molar masses, etc.

Step 1. Assemble all the information in one place

#M_text(r):color(white)(mml)138.21color(white)(mmmmmm)74.55#
#color(white)(mmmml)"K"_2"CO"_3 + "2HCl" → "2KCl" + "H"_2"O" + "CO"_2#
#m"/g": color(white)(m.l)41.46#

Step 2. Calculate the moles of #"K"_2"CO"_3#

#"Moles of K"_2"CO"_3 = 41.46 color(red)(cancel(color(black)("mg K"_2"CO"_3))) × ("1 mol K"_2"CO"_3)/(138.21 color(red)(cancel(color(black)("g K"_2"CO"_3)))) = "0.299 97 mmol K"_2"CO"_3#

Step 3 Calculate the moles of #"KCl"#

#"Moles of KCl" = "0299 97" color(red)(cancel(color(black)("mol K"_2"CO"_3)))× ("2 mol KCl")/(1 color(red)(cancel(color(black)("mol K"_2"CO"_3)))) = "0.599 96 mmol KCl"#

Step 4. Calculate the theoretical yield of #"KCl"#

#"Mass of KCl" = "0.599 96" color(red)(cancel(color(black)("mol NaI"))) × "74.55 g KCl"/(1 color(red)(cancel(color(black)("mol KCl")))) = "44.73 g KCl"#

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