What is the the vertex of #x = (y +2)^2 - 5y-2 #?

Question

1806 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-14T14:04:45

enter image source here

enter image source here

Answer 2 · 2018-06-14T14:10:02

#(7/4 , 1/2)#

#x = (y+2)^2-5y-2#

#x = (y^2 color(blue)(+4y) +4)color(blue)(-5y)-2#

#x = y^2 -y+2#

#x = (y- 1/2)^2 + 7/4#

#x- 7/4 = (y - 1/2)^2#

#"The vertex is at " (7/4,1/2)#