How do solve the following linear system?: # 2x+5y=1 , -6x-2y=-8 #? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Cem Sentin Jun 6, 2018 #x=19/13# and #y=-5/13# Explanation: #2*(2x+5y)+5*(-6x-2y)=2*1+5*(-8)# #4x+10y-30x-10y=2-40# #-26x=-38# So, #x=(-38)/(-26)=19/13# Hence, #2*19/13+5y=1# #38/13+5y=1# #5y=-25/13#, thus #y=-5/13# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1418 views around the world You can reuse this answer Creative Commons License