How do you graph the polar equation $r=-3sintheta$ ?

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Answer 1 · 2018-05-28T09:03:38

please show the graph below

As $r=-3sintheta$ ,at $theta=0,pi/4,pi/2,(3pi)/4 and pi$

$r$ takes values $r=0,(-3)/sqrt2,-3,(-3)/sqrt2,0$

Thus these represents points $(0,0),((-3)/sqrt2,pi/4),(-3,pi/2),((-3)/sqrt2,3pi/4),(0,pi)$

We can select more such points, say by having $theta=pi/6,pi/3,(2pi)/3, (5pi)/6$

the graph will be appear as follow:

james

it is a circle with center $(-3/2,-pi/2)$ and radius $r=3$

as $r=-3sintheta$ it means $r^2=-3rsintheta$

$x^2+y^2=-3y$

How do you graph the polar equation r=-3sinthetar=-3sintheta?