Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve the following linear system: $x = 1 - y, y = 2 x - 2$ $x=1-y , y=2x-2$ ?

1 Answer

May 24, 2018

$x = 1$ $x=1$ and $y = 0$ $y=0$

Explanation:

$x = 1 - (2 x - 2)$ $x=1-(2x-2)$

$x = 3 - 2 x$ $x=3-2x$

$3 x = 3$ $3x=3$ , so $x = 1$ $x=1$

Thus, $y = 2 \cdot 1 - 2 = 0$ $y=2*1-2=0$

Related questions

How do you solve systems of equations using the substitution method?
How do you check your solutions to a systems of equations using the substitution method?
When is the substitution method easier to use?
How do you know if a solution is "no solution" or "infinite" when using the substitution method?
How do you solve $y = - 6 x - 3$ $y=-6x-3$ and $y = 3$ $y=3$ using the substitution method?
How do you solve $12 y - 3 x = - 1$ $12y-3x=-1$ and $x - 4 y = 1$ $x-4y=1$ using the substitution method?
Which method do you use to solve the system of equations $y = \frac{1}{4} x - 14$ $y=1/4x-14$ and $y = \frac{19}{8} x + 7$ $y=19/8x+7$ ?
What are the 2 numbers if the sum is 70 and they differ by 11?
How do you solve $x + y = 5$ $x+y=5$ and $3 x + y = 15$ $3x+y=15$ using the substitution method?
What is the point of intersection of the lines $x + 2 y = 4$ $x+2y=4$ and $- x - 3 y = - 7$ $-x-3y=-7$ ?

See all questions in Systems Using Substitution

Impact of this question

2033 views around the world

You can reuse this answer
Creative Commons License