(4x+1)(3x-2)?

2 Answers
Michael · Stefan V.
May 23, 2018

#12x^2-5x-2#

Explanation:

Use F.O.I.L. (First, Outside, Inside, Last). Multiply the first terms, #4x# and #3x#, to get #12x^2#. Then the outside term, #4x# and #-2#, to get #-8x#.

Then the inside, #1# and #3x#, to get #3x#. Finally, the last terms, #1# and #-2#, to get #-2#. You now have

#12x^2-8x+3x-2#

This can be simplified to

#12x^2-5x-2#

Jim G.
May 23, 2018

#12x^2-5x-2#

Explanation:

#"each term in the second bracket is multiplied by"#
#"each term in the first bracket"#

#=(color(red)(4x+1))(3x-2)#

#=color(red)(4x)(3x-2)color(red)(+1)(3x-2)larrcolor(blue)"distribute"#

#=(color(red)(4x)xx3x)+(color(red)(4x)xx-2)+(color(red)(1)xx3x)+(color(red)(1)xx-2)#

#=12x^2color(blue)(-8x)color(blue)(+3x)-2larrcolor(magenta)"collect like terms"#

#=12x^2-5x-2#

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