How do you simplify #sqrt14-sqrt2/7#?

↳Redirected from "Question #c42fa"
2 Answers
Meave60
May 21, 2018

#sqrt14-(sqrt2)=color(blue)((7sqrt14-sqrt2)/7#

Explanation:

Simplify:

#sqrt14-(sqrt2)/7#

In order to add or subtract fractions, they must have the same denominator; the least common denominator (LCD). The LCD for this expression is #7#.

Multiply #sqrt14# by #7/7# to get an equivalent fraction with #7# as the denominator. Since #7/7=1#, the numbers will change, but the value will remain the same.

#sqrt14xx7/7-(sqrt2)/7#

Simplify #sqrt14xx7/7# to #(7sqrt14)/7#.

#(7sqrt14)/7-sqrt2/7#

Combine the numerators.

#(7sqrt14-sqrt2)/7#

Guillaume L.
May 21, 2018

#sqrt14-sqrt2/7=sqrt2(sqrt7-1/7)#

Explanation:

#sqrt14-sqrt2/7#
#=sqrt7*sqrt2-sqrt2/7#
#=sqrt2(sqrt7-1/7)#

Related questions
See all questions in Addition and Subtraction of Radicals
Impact of this question
2898 views around the world
You can reuse this answer
Creative Commons License