The sum of two numbers is 35 One number is 23 more than the other Solve to find each number Help please???

The sum can be defined as two numbers added together.

I would start by listing all the possible outcomes, although this can be time-consuming if a large number.

#1) 34 and 1#
#2) 33 and 2#
#3) 32 and 3#
#4) 31 and 4#
#5) 30 and 5#
#6) 29 and 6#
#7) 28 and 7#
#8) 27 and 8#
#9) 26 and 9#
#10) 25 and 10#

Now take away the smaller number from the bigger number:

#1)33#
#2)31#
#3)29#
#4)27#
#5)25#
#6)23#

Since #29-6=23# and #29+6=35#, these can be used

The sum of two numbers is #35#.

One number is #23# more than the other number.

So, if we subtract this additional #23# from the sum #35#, we are

left with the sum of two equal numbers.

Dividing this difference in two equal parts, we get

one number and the other one will be #23# more.

Thus, the desired numbers are, #1/2(35-23)=1/2*12=6# &

#6+23=29#.

Enjoy Maths.!

We can define the two numbers using one variable because we know the relationship between the numbers,

Let the smaller number be #x#

The larger number differs by #23#,. It will be #x+23#

The sum of the numbers is #35#

# x+x+23= 35#

#2x = 35-23#

#2x = 12#

#x =6" "larr# this is the smaller number,

The larger number is #6+23= 29#

Check: #6+29 =35" " and 29-23 =6#