What is ${(- 2 x^{2} y^{4})}^{3}$ $(-2x^2y^4)^3$ ?

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What is ${(- 2 x^{2} y^{4})}^{3}$ $(-2x^2y^4)^3$ ?

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Answer 1 · 2018-05-18T05:26:07

$- 8 x^{6} y^{12}$ $-8x^6y^12$

Explanation:

${(- 2)}^{3} = - 8$ $(-2)^3=-8$

${(x^{2})}^{3} = x^{2 \times 3} = x^{6}$ $(x^2)^3=x^(2 xx3)=x^6$

${(y^{4})}^{3} = y^{12}$ $(y^4)^3=y^12$

Answer 2 · 2018-05-18T05:29:05

$- 8 x^{6} y^{12}$ $-8x^6y^12$

Explanation:

${(a b c)}^{3} = a^{3} b^{3} c^{3}$ $(abc)^3 = a^3b^3c^3$ ,
so ${(- 2 x^{2} y^{4})}^{3} = {(- 2)}^{3} {(x^{2})}^{3} {(y^{4})}^{3}$ $(-2x^2y^4)^3=(-2)^3(x^2)^3(y^4)^3$ ,

and because ${(a^{b})}^{c} = a^{b c}$ $(a^b)^c=a^(bc)$ ,

${(- 2)}^{3} {(x^{2})}^{3} {(y^{4})}^{3} = - 8 x^{6} y^{12}$ $(-2)^3(x^2)^3(y^4)^3=-8x^6y^12$ .

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What is ${(- 2 x^{2} y^{4})}^{3}$ $(-2x^2y^4)^3$ ?

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Explanation:

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What is ${(- 2 x^{2} y^{4})}^{3}$ $(-2x^2y^4)^3$ ?