How do you solve #4x+8=32#? Algebra Linear Equations Two-Step Equations and Properties of Equality 1 Answer oscitare May 12, 2018 #x=6# Explanation: #4x+8=32# Isolate for #x#. Start by subtracting #8# from both sides of the equation. #4x+8 color(red)(-8) = 32 color(red)(-8)# #color(green)(4x=24)# Divide both sides of the equation by #4#. #color(green)(4x)/color(blue)(4)=color(green)(24)/color(blue)(4)# #color(purple)(x=6)# Answer link Related questions How do you solve two step equations? How do you check solutions to two step equations? What is an example of a two step equation with no solution? How do I check to see if the solution is 1 for the equation #2x+1=3#? Is there more than one way to solve a 2 step equation? How do you solve #-m+3=3#? How do you solve #-5y-9=74#? How do you solve #5q - 7 = \frac{2}{3}#? How do you solve #0.1y + 11 =0#? How do you solve #\frac{5q-7}{12} = \frac{2}{3}#? See all questions in Two-Step Equations and Properties of Equality Impact of this question 9977 views around the world You can reuse this answer Creative Commons License