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What is the derivative of # ln(sin^2x)#?

1 Answer

May 11, 2018

Use chain rule
#f(x)=h(g(x))#
#f'(x)=h'(g(x)) g'(x)#

Explanation:

#ln(sin^2(x))#

#(ln(sin^2(x)))'=#
#=1/(sin^2(x))*(sin^2(x))'=#

#=1/(sin^2(x))2*(sin(x))*(sin(x))'=#

#=2/(sin(x))*(cos(x))=2/tan(x)=2 cot(x)#

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