How do you solve $y = x^2 - 6x + 8 = 0$ using the quadratic formula?

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Answer 1 · 2018-05-09T20:54:00

Use the coefficients with the formula, and you will find that $x={2,4}$

The Quadratic Formula is written as follows:

$x=(-b+-sqrt(b^2-4ac))/(2a)$

Where the quadratic equation used looks like this:

$ax^2+bx+c=0$

Using this pattern, we can see the following:

$a=1$
$b=-6$
$c=8$

Let's plug these numbers into the formula:

$x=(-(-6)+-sqrt((-6)^2-4(1)(8)))/(2(1))$

$x=(6+-sqrt(36-32))/2$

$x=(6+-sqrt(4))/2=(6+-2)/2=3+-1$

$x={(3-1),(3+1)}$

$color(green)(x={2,4}$

How do you solve y = x^2 - 6x + 8 = 0y = x^2 - 6x + 8 = 0 using the quadratic formula?