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How do you find the derivative of $f (t) = 4 t^{3}$ $f(t)=4t^3$ ?

1 Answer

May 3, 2018

$= 12 t^{2}$ $=12t^2$

Explanation:

$\frac{d}{d t} (4 t^{3})$ $d/dt(4t^3)$

$4 \cdot 3^{3 - 1}$ $4*3^(3-1)$

$= 12 t^{2}$ $=12t^2$

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