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How do you solve #x^2-3x+2=0# using the quadratic formula?

1 Answer

May 2, 2018

#x_1=2 or x_2=1#

Explanation:

#x^2+px+q=0#
#x_(1,2)=-p/2+-sqrt((p/2)^2-q)#
#p=-3 and q=2#
#x_(1,2)=3/2+-sqrt(9/4-2)#
#x_1=3/2+1/2=2 or x_2=3/2-1/2=1#

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