How do you simplify #(6 + 6^2) times 3# using order of operations?

1 Answer
josh · Stefan V.
Apr 25, 2018

#=126#

Explanation:

#(6+6^2) xx 3#

#=(6 + 36) xx 3#

#= (42) xx 3#

#=126#

BEDMAS. Brackets go first, which is #6 + 6^2#. Inside the brackets, exponents go next, which turns the #6^2# to a #36#, which gives you #(6+36)#.

Then, to finalize the brackets, add them together. Then all you have left is #42# multiplied by #3#, which gives you #126#.

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