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How do you find the derivative of #f(x)= 1/x^2#?

1 Answer

Apr 22, 2018

#f'(x)=-2/x^3#

Explanation:

Rewrite the function with negative exponents, recalling that #1/x^a=x^-a#:

#f(x)=x^-2#

Apply the Power Rule, which tells us that if #f(x)=x^n, f'(x)=nx^(n-1):#

#f'(x)=-2x^(-2-1)#

#f'(x)=-2x^-3#

#f'(x)=-2/x^3#

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