How do you find the x and y intercepts of y=3x-2?

2 Answers
Apr 19, 2018

"x-intercept "=2/3," y-intercept "=-2

Explanation:

"To find the intercepts, that is where the graph crosses"
"the x and y axes"

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercept"

x=0rArry=0-2=-2larrcolor(red)"y-intercept"

y=0rArr3x-2=0rArrx=2/3larrcolor(red)"x-intercept"
graph{(y-3x+2)((x-0)^2+(y+2)^2-0.04)((x-2/3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

Apr 19, 2018

"y-intercept " = (0, -2) or -2
"y-intercept " = (2/3, 0) or 2/3

Explanation:

The y-intercept is when the value of x = 0. Therefore, plugging in the value of x into the equation:

3(0) - 2 = -2 " So, " y = -2 This is for the y-intercept

The x intercept is when y = 0, substituting this into the equation gives us:

0 = 3x - 2 It is possible to rearrange this:

0 -3x = 3x - 3x - 2
3x = 2
x = 2/3