How do you solve the system of equations #2x+3y=105# and #x+2y=65#?

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Answer 1 · 2018-04-19T02:35:01

#x# equals #15# and #y# equals #25#.

Set the easiest equation to #x# (the last one) and because

#x = -2y+65#

the #x# in the other equation also equals that, you can replace the #x# in the first equation with the #-2y+65#. Then simplify and solve for the #y#.

You can plug the #25# into either equation to simplify and solve for #x#.

Looks like:

#x=-2y+65#

so

#2(-2y+65)+3y=105#

#-4y+3y=105-130#

#y=25#

And

#x+2(25)=65#

#x=15#