How do you solve #4sinx=-2sinx-5#?

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Answer 1 · 2018-04-18T16:51:46

# x = npi -(-1)^nsin^(-1)(5/6)#

#4sinx=-2sinx-5#

#rArr 6sinx=-5#
#rArrsinx=-5/6#

Now writing down the general solution for #sinx=sintheta# :-

#rArr x = npi +(-1)^nsin^(-1)(-5/6)#

#:. x = npi -(-1)^nsin^(-1)(5/6)#.........{#sin^(-1)(-theta)=-sin^(-1)theta#}

Here #n# is any Integer value.