How do you solve by substitution $3 x + 2 y = 11$ $3x + 2y = 11$ and $x - 2 = - 4 y$ $x - 2 = -4y$ ?

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How do you solve by substitution $3 x + 2 y = 11$ $3x + 2y = 11$ and $x - 2 = - 4 y$ $x - 2 = -4y$ ?

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Answer 1 · 2018-04-17T21:03:01

$(4, - \frac{1}{2})$ $(4,-1/2)$

Explanation:

$3 x + 2 y = 11 and x - 2 = - 4 y$ $3x+2y=11 and x-2 =-4y$
Step 1:Choose an equation $x - 2 = - 4 y$ $x-2 =-4y$
Step 2: Isolate a variable $x = - 4 y + 2$ $x =-4y +2$
Step 3: Substitute $- 4 y + 2$ $-4y +2$ for $x$ $x$ in the other equation
$3 (- 4 y + 2) + 2 y = 11$ $3(-4y+2)+2y=11$
Step 4:Distribute $- 12 y + 6 + 2 y = 11$ $-12y+6+2y=11$
Step 5:Simplify $- 10 y = 5$ $-10y=5$
Step 6: Find $y$ $y$ value $y = - \frac{1}{2}$ $y=-1/2$
Step 7: Plug y value back into any equation $x - 2 = - 4 (- \frac{1}{2})$ $x-2 =-4(-1/2)$
Step 8:Solve for "x " $x = 4$ $x=4$

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How do you solve by substitution $3 x + 2 y = 11$ $3x + 2y = 11$ and $x - 2 = - 4 y$ $x - 2 = -4y$ ?

1 Answer

Explanation:

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How do you solve by substitution $3 x + 2 y = 11$ $3x + 2y = 11$ and $x - 2 = - 4 y$ $x - 2 = -4y$ ?