What is the distance between #(1, 4)# and #(-6, -7)#?

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Answer 1 · 2018-04-16T23:59:07

#d = sqrt(170)#

d= 13.04 units

To find the distance between points at #(1,4)# and #(-6,-7)#

#d = sqrt((y_2-y_1)^2 + (x_2-x_1)^2)#

for the points given
#x_1 = 1#
#y_1 = 4#
#x_2 = -6#
#y_2 = -7#

plugging in the values we get
#d = sqrt((-7-4)^2 + (-6-1)^2)#

simplifying the parenthesis
#d = sqrt((-11)^2 + (-7)^2)#

Simplifying the squares
#d = sqrt(121 + 49)#

simplifying the radical
#d = sqrt(170)#

d= 13.04 units