What is the equation of the line perpendicular to $y=-3/7x$ that passes through $(8,5)$ ?

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What is the equation of the line perpendicular to $y=-3/7x$ that passes through $(8,5)$ ?

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Answer 1 · 2018-04-13T03:58:40

y = $7/3x - 41/3$

Explanation:

For perpendicular lines, the product of their slopes is -1
The slope of the line is $-3/7$
Hence, the slope of the line perpendicular is ( $-1/(-3/7)$ ) = $7/3$
$y-y1 = m(x-x1)$
y-5 = $7/3$ (x - 8)
y = $7/3x - 56/3 +5$
y = $7/3x - 41/3$

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What is the equation of the line perpendicular to $y=-3/7x$ that passes through $(8,5)$ ?

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What is the equation of the line perpendicular to y=-3/7x y=-3/7x that passes through (8,5) (8,5) ?

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Explanation:

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What is the equation of the line perpendicular to $y=-3/7x$ that passes through $(8,5)$ ?