How do you solve $8 (r - 8) + 4 r = - 136$ $8( r - 8) + 4r = - 136$ ?

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Answer 1 · 2018-04-12T11:24:12

$r = - 6$ $r=-6$

$8 (r - 8) + 4 r = - 136$ $8(r-8)+4r=-136$ (Distribute 8 to the number in braces)

$8 r - 64 + 4 r = - 136$ $8r-64+4r=-136$ (Combine like terms)

$12 r - 64 = - 136$ $12r-64=-136$ (Add 64 to both sides)

$12 r = - 72$ $12r=-72$ (Divide both sides by 12)

$r = - 6$ $r=-6$

Check the answer by plugging into the original equation:

$8 (- 6 - 8) + 4 (- 6) = - 136$ $8(-6-8)+4(-6)=-136$

$8 (- 14) - 24 = - 136$ $8(-14)-24=-136$

$- 112 - 24 = - 136$ $-112-24=-136$

$- 136 = 136$ $-136=136$

How do you solve 8(r−8)+4r=−1368( r - 8) + 4r = - 136?