How do you solve #8( r - 8) + 4r = - 136#?

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Answer 1 · 2018-04-12T11:24:12

#r=-6#

#8(r-8)+4r=-136# (Distribute 8 to the number in braces)

#8r-64+4r=-136# (Combine like terms)

#12r-64=-136# (Add 64 to both sides)

#12r=-72# (Divide both sides by 12)

#r=-6#

Check the answer by plugging into the original equation:

#8(-6-8)+4(-6)=-136#

#8(-14)-24=-136#

#-112-24=-136#

#-136=136#