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How do you solve #x + y = 5# and #2x + y = 7 # using substitution?

1 Answer

Apr 9, 2018

#x=2#
#y=3#

Explanation:

You can re-arrange equation #x+y=5# to get #x=5-y# and then substitute this into the equation #2x+y=7# to get #2(5-y)+y=7#.

This can then be simplified to #10-y=7# and so #3-y=0# which means #y=3#.

Substitute #y=3# into #x+y=5# and you get #x+3=5#, therefore:
#x=2#
#y=3#

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