How do you solve #x^2=-9x-8#?

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How do you solve #x^2=-9x-8#?

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Answer 1 · 2018-04-09T02:04:19

x= -1 or-8

Explanation:

First use null factor law to put the #-x^2# on the other side hence making 0= #-x^2# -9x-8. Simplify by dividing by-1 = #x^2# +9x+8=0. Then use cross method to factorise which becomes (x+8)(x+1)=0 the x being -8 or -1 as the answer

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How do you solve #x^2=-9x-8#?

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