How do you evaluate #6^5/6^2#?

2 Answers
Apr 2, 2018

#6^3# = 216

Explanation:

Using the index laws
#(a^m)/(a^n)# = #a^(m-n)#

#6^5/6^2# = #6^(5-2)# = #6^3# = 216

Apr 2, 2018

#6^3# = 216

Explanation:

When dividing two numbers with exponents, which have the same base, you can just subtract the exponents from eachother like this:
#(a^b)/(a^c) = a^(b-c) #
and similarly (eventhough its not relevant to this problem,)
# (a^b)*(a^c) = a^(b+c) #
therefor:
# (6^5)/(6^2) = 6^(5-2) = 6^3 = 6*6*6 = 216#