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How do you find the derivative of #f(x)= (x^3)(e^(2x))#?

1 Answer

Mar 31, 2018

#dy/dx = x^2e^{2x}(3+2x)#

Explanation:

#d/dx[uv] = {du}/dx v + {dv}/dx u#

#u=x^3#
#v=e^{2x}#

#dy/dx = d/dx[x^3]e^{2x}+d/dx[e^{2x}]x^3#

#dy/dx = 3x^2e^{2x}+2e^{2x}x^3#

#dy/dx = x^2e^{2x}(3+2x)#

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