How do you solve the following linear system: $5 x + 8 y = 1, - 2 x + 3 y = 4,$ $5x+8y=1, -2x+3y=4,$ ?

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How do you solve the following linear system: $5 x + 8 y = 1, - 2 x + 3 y = 4,$ $5x+8y=1, -2x+3y=4,$ ?

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Answer 1 · 2018-03-30T16:51:09

It can be solved by,
- Elimination method.
- Substitution method.

Explanation:

1)By elimination method,
$5 x + 8 y = 1 - - (I) e q n$ $5x+8y=1--(I) eqn$
$2 x + 3 y = 4 - - (I I) e q n$ $2x+3y=4--(II)eqn$
multiply eqn (I) by 2 & eqn (II) by 5,
$10 x + 16 y = 2 - - (3) e q n$ $10x+16y=2--(3)eqn$
$10 x + 15 y = 20 - - (4) e q n$ $10x+15y=20--(4)eqn$
after solving further, will give
$y = - 18$ $y=-18$
so, $x = 29$ $x=29$

2)By substitution method,
$5 x + 8 y = 1$ $5x+8y=1$
$x = \frac{1 - 8 y}{5} - - (1)$ $x=(1-8y)/5--(1)$
$2 x + 3 y = 4 - - (2)$ $2x+3y=4--(2)$
put value of x in eqn(2)
$2 (\frac{1 - 8 y}{5}) + 3 y = 4$ $2((1-8y)/5)+3y=4$
$\frac{2 - 16 y}{5} + 3 y = 4$ $(2-16y)/5+3y=4$
$\frac{2 - 16 y + 15 y}{5} = 4$ $(2-16y+15y)/5=4$
$2 - y = 20$ $2-y=20$
$y = - 18$ $y=-18$
so, $x = \frac{1 - 8 (- 18)}{5}$ $x=(1-8(-18))/5$
$x = \frac{1 + 144}{5}$ $x=(1+144)/5$
$x = \frac{145}{5}$ $x=145/5$
$x = 29$ $x=29$

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How do you solve the following linear system: $5 x + 8 y = 1, - 2 x + 3 y = 4,$ $5x+8y=1, -2x+3y=4,$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you solve the following linear system: 5x+8y=1,−2x+3y=4, 5x+8y=1, -2x+3y=4, ?

1 Answer

Explanation:

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How do you solve the following linear system: $5 x + 8 y = 1, - 2 x + 3 y = 4,$ $5x+8y=1, -2x+3y=4,$ ?