How do you solve #3y^2+2y-1=0#?

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How do you solve #3y^2+2y-1=0#?

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Answer 1 · 2018-03-30T15:01:38

#y=-1, 1/3#

Explanation:

#3y^2+3y-y-1=0# find two integers that ADD to 2, MULTIPLY to -3 #(3*-1)#
#3y(y+1)-(y+1)# factor out common factor
#(3y-1)(y+1)#
#3y-1 = 0# OR #y+1=0#
#y=1/3# OR #y=-1#

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How do you solve #3y^2+2y-1=0#?

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