How do you simplify $((3x^2)(6y^4)(z^2))/((12x)(3y^2)(z))$ ?

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Answer 1 · 2018-03-29T10:16:37

$(2xy^2z)/(4x)$

To simply we know that the numbers divide $3/12=1/4$

We also know that for the exponents they subtract when we divide $y^4/y^2=y^(4-2)=y^2$

So $(3x^2)/(12x)=(1x)/4$ ,

$(6y^4)/(3y^2)=2y^2$

$z^2/z=z$

So if we mutiply all these part together we get

$(2xy^2z)/(4x)$

How do you simplify ((3x^2)(6y^4)(z^2))/((12x)(3y^2)(z))((3x^2)(6y^4)(z^2))/((12x)(3y^2)(z))?