How do you write an equation in slope-intercept form for an equation of a line perpendicular to #y = -3x +1# and that intersects at point #(1, 2/3)#?

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How do you write an equation in slope-intercept form for an equation of a line perpendicular to #y = -3x +1# and that intersects at point #(1, 2/3)#?

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Answer 1 · 2018-03-29T07:30:28

#3y=x+1#

Explanation:

The slope of this line is #-3#. Slope of a line perpendicular to it it #1/3#.
Because #m_1*m_2=-1# where #m_1# and #m_2# are the slope of perpendicular lines

Now, the equation of the line is #y=x/3+c#

To find #c#, put a point which in this case is #(1,2/3)#

#2/3=1/3+c# #=># We get that #c=1/3#

So required equation is #y=x/3+1/3# or #3y=x+1#

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How do you write an equation in slope-intercept form for an equation of a line perpendicular to #y = -3x +1# and that intersects at point #(1, 2/3)#?

1 Answer

Explanation:

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