How do you solve #6+ 2x = 38#?

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Answer 1 · 2018-03-28T18:21:00

#x=16#

#6+2x=38# (Subtract 6 from both sides)

#2x=32# (Divide both sides by 2 to isolate the variable)

#x=16#

Check the answer by plugging in the answer into the initial equation:

#6+ 2(16) =38#

#6+32=38#

#38=38#

Answer 2 · 2018-03-28T18:25:14

#x=16#

So first you have to subtract #6# from both sides. When you subtract from #38#, you get #32#. Now you just have

#2x=32#

left. This is when you use division to get #x# by itself. Now you divide by #2# on both sides

#(2x)/2 = 32/2#

and you do that to get #x# alone. So now it's just

#x=16#

because #32/2# is #6#.