How do you simplify $6 \times (2 \div 1) \div 1$ $6 times (2 ÷ 1) ÷ 1$ using order of operations?

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Answer 1 · 2018-03-28T16:32:41

12

Order of Operations goes like this:

Parentheses ()
Exponents $1^{2}$ $1^2$
Multiplication/Division $\cdot$ $*$ or $/$ $/$
Addition/Subtraction $+$ $+$ or $-$ $-$

Using this, we get...

$6 \cdot \frac{2}{1}$ $6*2/1$ because we removed the parentheses

Now, we do this left to right.

$6 \cdot 2 = 12$ $6*2=12$

$\frac{12}{1} = 12$ $12/1=12$

Yay!

How do you simplify 6 times (2 ÷ 1) ÷ 16×(2÷1)÷16 times (2 ÷ 1) ÷ 1 using order of operations?