How do you solve 3log2x=4?

1 Answer
Soumalya Pramanik ยท Anish M.
Mar 25, 2018

x=(1/2)*10^(4/3)

Explanation:

Assuming the logarithm as Common Logarithm (With base 10),

color(white)(xxx)3log2x=4

rArr log2x=4/3 [Transposing The 3 to R.H.S.]

rArr 2x=10^(4/3) [According to The Definition of Logarithm]

rArr x=(1/2)*10^(4/3) [Transposing 2 to R.H.S]

Hope this helps.

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