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How do you solve $3 log 2 x = 4$ $3log2x=4$ ?

1 Answer

Soumalya Pramanik · Anish M.

Mar 25, 2018

$x = (\frac{1}{2}) \cdot 10^{\frac{4}{3}}$ $x=(1/2)*10^(4/3)$

Explanation:

Assuming the logarithm as Common Logarithm (With base $10$ $10$ ),

$\times x 3 log 2 x = 4$ $color(white)(xxx)3log2x=4$

$\Rightarrow log 2 x = \frac{4}{3}$ $rArr log2x=4/3$ [Transposing The 3 to R.H.S.]

$\Rightarrow 2 x = 10^{\frac{4}{3}}$ $rArr 2x=10^(4/3)$ [According to The Definition of Logarithm]

$\Rightarrow x = (\frac{1}{2}) \cdot 10^{\frac{4}{3}}$ $rArr x=(1/2)*10^(4/3)$ [Transposing 2 to R.H.S]

Hope this helps.

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