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How do you divide #(x^4+2x^3-2x^2+9x+3)/(x^2+1) #?

1 Answer

Mar 24, 2018

#x^2+2x-3+(7x+6)/(x^2+1)#

Explanation:

By long division

#(x^4+2x^3-2x^2+9x+3):(x^2+1)=x^2#
#-x^4-x^2#

#(0+2x^3-3x^2+9x+3):(x^2+1)=x^2+2x#
#-2x^3-2x#

#(0+0-3x^2+7x+3):(x^2+1)=x^2+2x-3#
#+3x^2+3#

#(0+0+0+7x+6):(x^2+1)=x^2+2x-3#

#x^2+2x-3+(7x+6)/(x^2+1)#

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