Solve the equation 3y²=27?

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Solve the equation 3y²=27?

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Answer 1 · 2018-03-22T18:46:25

$y = \pm 3$ $y = +-3$

Explanation:

$3 y^{2} = 27 \leftarrow$ $3color(blue)(y^2) =27" "larr$ to isolate the $y^{2}, \div 3$ $y^2, div 3$ on both sides

$\frac{3 y^{2}}{3} = \frac{27}{3}$ $(3color(blue)(y^2))/3 =27/3$

$y^{2} = 9$ $y^2= 9$

$y = \pm \sqrt{9}$ $y = +-sqrt9$

$y = \pm 3$ $y = +-3$

Answer 2 · 2018-03-22T18:51:39

y = 3 or y = -3

Explanation:

$3 y^{2} = 27$ $3y^2 = 27$ (divide both sides by 3)
$y^{2} = 9$ $y^2 = 9$ (take the square root of both sides)
$y = \pm \sqrt{9}$ $y = +-sqrt(9)$
$y = \pm 3$ $y = +-3$

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Solve the equation 3y²=27?

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