How do you solve systems of equations by solution 2x-3y=-1 and y=x-1?

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Answer 1 · 2018-03-21T04:27:58

#x=1# and #y=-1#

#2x-3y=-1" " " "(1)#

#y=x-1" " " "(2)#

#(2)# can be written as

#x-y= 1#

Therefore

#x-y=1" "# (multiply by #2#)

#2x - 2y= 2" " " "(3)#

So, #(1)-(3)#

# 2x-3y= -1#
# -2x+2y= 2#

# -y= 1#

Therefore

#y=-1 #

Now substitute the value of #y# in #(1)#

#2x-3(-1)= 1#

#2x+3=1#

#2x=3-1#

#x= 2/2#

#x= 1#

Therefore

#x=1# and #y=-1#