How do you write $5^{x} = 25$ $5^x=25$ in log form?

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Answer 1 · 2018-03-16T18:16:44

I tried this:

I would use the definition of log:
${log}_{b} a = x$ $log_ba=x$
so that: $b^{x} = a$ $b^x=a$

In our case we have:
$5^{x} = 25$ $5^x=25$
so that we get:
${log}_{5} (25) = x$ $log_5(25)=x$

By the way: $x = 2$ $x=2$

Answer 2 · 2018-03-16T18:17:17

${log}_{5}$ $log_5$ $25 = x$ $25=x$

$5^{x} = 25$ $5^x=25$
$5^{x} = 5^{2}$ $5^x=5^2$
$x = 2$ $x=2$ (By comparing)

How do you write 5x=255^x=25 in log form?