How to find the x and y-intercept given #y= -2x + 4 #?

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Answer 1 · 2018-03-16T04:24:37

#y#-int #= 4#

#x#-int #= 2#

To find the #y#-intercept, you simply substitute in a #0# for #x#, which would give you the equation

#y = -2(0) + 4#

which then you simplify to get

#y = 4#

To find the #x#-intercept, you set #y# equal to #0#, which would give you the equation

#0 = -2x + 4#

then you move the #4# to the other side by subtracting

#-4 = -2x#

And finally, you divide both sides by #-2# to get

#x = 2#