How do you solve $7 (2 x - 3) = 4 (2 - x)$ $7( 2x - 3) = 4( 2- x )$ ?

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Answer 1 · 2018-03-13T23:33:56

$x = \frac{29}{18}$ $x=\frac{29}{18}$

Subtract $4 (2 - x)$ $4(2-x)$ from both sides.
$7 (2 x - 3) - 4 (2 - x) = 0 \Leftrightarrow$ $7(2x-3)-4(2-x)=0 \iff$
Perform the multiplications.
$14 x - 21 - (8 - 4 x) = 0 \Leftrightarrow$ $14x-21-(8-4x)=0 \iff$
Perform the additions/subtractions.
$18 x - 29 = 0 \Leftrightarrow$ $18x-29=0 \iff$
Add $29$ $29$ to both sides and then divide by $18$ $18$ .
$x = \frac{29}{18}$ $x=\frac{29}{18}$

How do you solve 7(2x−3)=4(2−x)7( 2x - 3) = 4( 2- x )?