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How do you solve #L = a + (n - L)d# for d?

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1 Answer

Mar 9, 2018

#d=(L-a)/(n-L)#

Explanation:

Subtract #a# from both sides.

#L-a=(n-L)d#

Divide both sides by #(n-L)#

#(L-a)/(n-L)=d#

Rewrite

#d=(L-a)/(n-L)#

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