How do you solve #96= 3( 4x + 8)#?

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Answer 1 · 2018-03-08T20:18:49

#x=6#

#96=3(4x+8)#

Step 1: Simplify both sides of the equation.

#96=3(4x+8)#
#96=(3)(4x)+(3)(8)" "#(Distribute)
#96=12x+24#

Step 2: Flip the equation.

#12x+24=96#

Step 3: Subtract #24# from both sides.
#12x+24−24=96−24#
#12x=72#

Step 4: Divide both sides by #12#
#(12x)/12 = =72/12#

#x=6#

Answer 2 · 2018-03-08T20:22:17

#x=6#

In order to solve the equation, you need to isolate the #x# term.

Rather than removing the brackets by distributing the #3# into the bracket, you can divide both sides by #3#.

#(cancel3(4x+8))/cancel3 = (cancel96 32)/cancel3#

#" "4x+8 = 32" "larr# subtract #8# from each side.

#4x +8color(blue)(-8) = 32color(blue)(-8)#

#" "4x = 24" "larr div4#

#" "x=6#