What is the derivative of $y = 2 x^{2} - 5$ $y = 2x^2 - 5$ ?

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What is the derivative of $y = 2 x^{2} - 5$ $y = 2x^2 - 5$ ?

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Answer 1 · 2018-03-06T16:22:50

The derivative is $4 x$ $4x$ .

Explanation:

For this, we can use the power rule: $\frac{d}{d x} a x^{n} = n a x^{n - 1}$ $\frac d dx ax^n = nax^(n-1)$ .

So, if we have $y = 2 x^{2} - 5$ $y=2x^2 -5$ , the only term that involves an x is the $2 x^{2}$ $2x^2$ , so that is the only term we have to find the derivative of. (The derivative of a constant such as $- 5$ $-5$ will always be 0, so we don't have to worry about it since adding or subtracting 0 won't change our overall derivative.)

Following the power rule, $\frac{d}{d x} 2 x^{2} = 2 (2) x^{2 - 1} = 4 x$ $\frac d dx 2x^2 = 2(2)x^(2-1) = 4x$ .

Answer 2 · 2018-03-06T16:23:22

4x

Explanation:

the power rule goes as

$\frac{d}{d x} c \cdot x^{n} = n \cdot c \cdot x^{n - 1}$ $d/dx c*x^n = n*c*x^(n-1)$

$2 x^{2} - 5$ $2x^2 - 5$

$= 2 x^{2} - 5 x^{0}$ $= 2x^2 - 5x^0$

the 2 and 0 comes down to the front and you subtract one from the power

=
$2 \cdot 2 x^{2 - 1} - 0 \cdot 5 \cdot x^{0 - 1}$ $2*2x^(2-1) - 0*5*x^(0-1)$

=
$4 x$ $4x$
=

and that's it

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What is the derivative of $y = 2 x^{2} - 5$ $y = 2x^2 - 5$ ?

2 Answers

Explanation:

Explanation:

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What is the derivative of y=2x2−5y = 2x^2 - 5?

2 Answers

Explanation:

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What is the derivative of $y = 2 x^{2} - 5$ $y = 2x^2 - 5$ ?