How do you simplify #6 ÷ (17 - 11) times 14# using order of operations?

3 Answers
smendyka
Mar 3, 2018

See a solution process below:

Explanation:

First, execute the operation within the Parenthesis;

#6 -: (color(red)(17) - color(red)(11)) xx 14 =>#

#6 -: 6 xx 14#

Next, execute the Multiplication and Division operations from left to right:

#color(red)(6) -: color(red)(6) xx 14 =>#

#1 xx 14 =>#

#14#

Deepesh Pandey
Mar 3, 2018

14 !!

Explanation:

It could be written as #6/(6)*14#= 1*14=14
Just use the BODMAS principle giving more preference to division than to multiplication.

CountryGirl
Mar 3, 2018

14

Explanation:

Order of operations follows this order:
- P (Parentheses)
- E (Exponents)
- MD (Multiplication and Division - left to right)
- AS (Addition and Subtraction - left to right)
Or PEMDAS for short.

So when we see:
#6÷(17−11)×14#
We know do the Parentheses first. So lets solve the part inside the parentheses:
#6÷(6) ×14#
There aren't any Exponents in this equation, so we can skip that part. But there is multiplication and division! So we will solve the those parts (don't forget: Go left to right! )
#6÷6 ×14#
#1 ×14#
#14#

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