How do you simplify $4 a + 5 a^{2} + 2 a^{2} + a^{2}$ $4a+5a^2+2a^2+a^2$ ?

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How do you simplify $4 a + 5 a^{2} + 2 a^{2} + a^{2}$ $4a+5a^2+2a^2+a^2$ ?

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Answer 1 · 2018-03-03T19:26:59

$4 a + 8 a^{2}$ $4a+8a^2$

Explanation:

Terms which are raised to the same power of the unknown can be added together. In this case, we have 3 terms to the power of "2" and one term to the power of "1".

Hence we can add the common terms: $5 a^{2} + 2 a^{2} + a^{2} = 8 a^{2}$ $5a^2 + 2a^2 + a^2=8a^2$ Then we simply add the remained which we can not add. Hence:

$4 a + 8 a^{2}$ $4a+8a^2$

Answer 2 · 2018-03-03T19:30:59

That can be simplified into $a (8 a + 4)$ $a(8a+4)$ or $8 a^{2} + 4 a$ $8a^2+4a$

Explanation:

Start by adding the like terms together, that is (terms of $a^{2}$ $a^2$ )
$5 a^{2} + 2 a^{2} + a^{2} = 8 a^{2}$ $5a^2+2a^2+a^2 = 8a^2$

Now you can rewrite it as $4 a + 8 a^{2}$ $4a + 8a^2$

The key here is that you can always add the like terms..
For example,

$6 x^{2} + 3 x + 4 x^{2} + 2 x + 3 y + 3 y^{2}$ $6x^2 + 3x + 4x^2 + 2x + 3y + 3y^2$
Here all the $x^{2}$ $x^2$ terms can be added together, all the $x$ $x$ terms can be added together, all the $y$ $y$ terms can be added together and all the $y^{2}$ $y^2$ terms can be added together..

So we get
$10 x^{2} + 5 x + 3 y^{2} + 3 y$ $10x^2 + 5x + 3y^2 + 3y$

Can be simplified even further by factoring out the $5 x$ $5x$ from first 2 terms and $3 y$ $3y$ from the next two terms,
$5 x (2 x + 1) + 3 y (y + 1)$ $5x(2x+1) + 3y(y+1)$

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How do you simplify $4 a + 5 a^{2} + 2 a^{2} + a^{2}$ $4a+5a^2+2a^2+a^2$ ?

2 Answers

Explanation:

Explanation:

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How do you simplify $4 a + 5 a^{2} + 2 a^{2} + a^{2}$ $4a+5a^2+2a^2+a^2$ ?