How do you simplify $sqrt(36a^4b^10)$ ?

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Answer 1 · 2018-03-02T05:05:02

$6a^2b^5$

$sqrt(36a^4b^10)$

$(36a^4b^10)^(1/2)$

$(36)^(1/2)(a^4)^(1/2)(b^10)^(1/2)$

$sqrt36a^2b^5$

$6a^2b^5$

For your information, taking the square root and raising to the power of $1/2$ is the same thing.

For example:

$5^2=25$

$sqrt(5^2)=sqrt25$

$sqrt(5^2)=5$

so that must mean that taking a square root is really taking it to the $1/2$ because

$5^(2*1/2)=5$

$5^1=5$

Answer 2 · 2018-03-02T05:05:33

$6a^2b^5$

$sqrt(36a^4b^10) = sqrt36 * sqrt(a^4) * sqrt(b^10)$

$=6*a^2*sqrt((b^5)^2)$

$=6a^2*b^5$

$=6a^2b^5$

Thus, we have our answer.

How do you simplify sqrt(36a^4b^10)sqrt(36a^4b^10)?