If you have a gas with an initial pressure of 5 atm and it occupies a volume of 10L. If you increase the volume to 13L, what will the new pressure of the gas be?

Question

4772 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-26T04:45:35

$"4 L"$

Use Boyle's Law

$"pressure(1)" xx "volume(1)" = "pressure(2)" xx "volume(2)"$

where

$"pressure(1) = 5 atm"$

$"volume(1) = 10 L"$

$"pressure(2)" = "13 atm"$

Therefore

$"5 atm" xx "10 L" ="13 atm" xx "volume(2)"$

$"volume(2)" = ("5 atm" xx "10 L")/"13 atm" = "3.85 L" = "4 L" ->$ one sigfig