If you have a gas with an initial pressure of 5 atm and it occupies a volume of 10L. If you increase the volume to 13L, what will the new pressure of the gas be?

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Answer 1 · 2018-02-26T04:45:35

#"4 L"#

Use Boyle's Law

#"pressure(1)" xx "volume(1)" = "pressure(2)" xx "volume(2)"#

where

#"pressure(1) = 5 atm"#

#"volume(1) = 10 L"#

#"pressure(2)" = "13 atm"#

Therefore

#"5 atm" xx "10 L" ="13 atm" xx "volume(2)"#

#"volume(2)" = ("5 atm" xx "10 L")/"13 atm" = "3.85 L" = "4 L" -># one sigfig