What is the Cartesian form of $( 3, (-5pi)/2 )$ ?

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Answer 1 · 2018-02-14T08:36:02

Using the formulas:
$x=r*cos(theta)$
$y=r*sin(theta)$

our answer is $(0,-3)$ in Cartesian

To convert from Polar coordinates to Cartesian, we must apply the following formulas:

$x=r*cos(theta)$
$y=r*sin(theta)$

where polar form is $(r,theta)$
and Cartesian form is $(x,y)$

for x:
$x=3*cos(-5pi/2) = 3*0 = 0$

$y=3*sin(-5pi/2) = 3*-1 = -3$

thus converting from polar to Cartesian:

Cartesian = $(0,-3)$

What is the Cartesian form of ( 3, (-5pi)/2 ) ( 3, (-5pi)/2 ) ?