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What is #lim_(x->+oo) x/(1-2x)#?

1 Answer

Feb 14, 2018

#lim_(x->oo)x/(1-2x)=-1/2#

Explanation:

#\ \ \ \ \ \ lim_(x->oo)x/(1-2x)#

Dividing both the numerator and denominator by #x#:
#=lim_(x->oo)1/(1/x-2)#

Now, as #x->oo#, the above limit slowly converges to #-1/2#.

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